Quick reference table

Common specific heat capacity conversions

FromTo
1 kJ/(kg·K)0.2388458966 BTU/(lb·°F)
1 cal/(g·°C)4,184 J/(kg·K)
1 J/(g·K)1 kJ/(kg·K)
1 kcal/(kg·K)4.184 kJ/(kg·K)

How to convert specific heat capacity

Specific heat capacity is how much energy it takes to raise one kilogram of a material by one degree. Water's is about 4.18 kJ/(kg·K), which is why it stores heat so well.

Every specific heat capacity unit is a fixed multiple of one base unit, the J/(kg·K). To convert a value, multiply it by the size of the starting unit and divide by the size of the target unit. For example, to convert kJ/(kg·K) to BTU/(lb·°F), multiply by 0.2388458966. To go the other way, divide by 0.2388458966.

The converter above does this for you and shows the exact formula under the result.

Worked examples

10 kJ/(kg·K) = 2.3884590 BTU/(lb·°F)10 × 0.2388458966 = 2.388458966 BTU/(lb·°F).
25 cal/(g·°C) = 104,600 J/(kg·K)25 × 4,184 = 104,600 J/(kg·K).
5 J/(g·K) = 5 kJ/(kg·K)5 × 1 = 5 kJ/(kg·K).
50 kcal/(kg·K) = 209.2 kJ/(kg·K)50 × 4.184 = 209.2 kJ/(kg·K).

Kilojoules per kilogram-kelvin to BTU per pound-degree F

Kilojoules per kilogram-kelvin (kJ/(kg·K))BTU per pound-degree F (BTU/(lb·°F))
1 kJ/(kg·K)0.2388458966 BTU/(lb·°F)
2 kJ/(kg·K)0.4776917933 BTU/(lb·°F)
5 kJ/(kg·K)1.194229483 BTU/(lb·°F)
10 kJ/(kg·K)2.388458966 BTU/(lb·°F)
25 kJ/(kg·K)5.971147416 BTU/(lb·°F)
50 kJ/(kg·K)11.94229483 BTU/(lb·°F)
100 kJ/(kg·K)23.88458966 BTU/(lb·°F)
1,000 kJ/(kg·K)238.8458966 BTU/(lb·°F)

Calories per gram-degree C to Joules per kilogram-kelvin

Calories per gram-degree C (cal/(g·°C))Joules per kilogram-kelvin (J/(kg·K))
1 cal/(g·°C)4,184 J/(kg·K)
2 cal/(g·°C)8,368 J/(kg·K)
5 cal/(g·°C)20,920 J/(kg·K)
10 cal/(g·°C)41,840 J/(kg·K)
25 cal/(g·°C)104,600 J/(kg·K)
50 cal/(g·°C)209,200 J/(kg·K)
100 cal/(g·°C)418,400 J/(kg·K)
1,000 cal/(g·°C)4,184,000 J/(kg·K)

Specific heat capacity units explained

UnitSymbolEquals
Joules per kilogram-kelvinJ/(kg·K)1 J/(kg·K) = 1 J/(kg·K)
Kilojoules per kilogram-kelvinkJ/(kg·K)1 kJ/(kg·K) = 1,000 J/(kg·K)
Joules per gram-kelvinJ/(g·K)1 J/(g·K) = 1,000 J/(kg·K)
Calories per gram-degree Ccal/(g·°C)1 cal/(g·°C) = 4,184 J/(kg·K)
Kilocalories per kilogram-kelvinkcal/(kg·K)1 kcal/(kg·K) = 4,184 J/(kg·K)
BTU per pound-degree FBTU/(lb·°F)1 BTU/(lb·°F) = 4,186.8 J/(kg·K)

Popular conversions: j/kg k to cal/g c.

Frequently asked questions

What is the specific heat of water?

About 4,184 J/(kg·K), or 1 cal/(g·°C) by the definition of the calorie.

How do I convert kJ/(kg·K) to BTU/(lb·°F)?

Multiply the value in kJ/(kg·K) by 0.2388458966 to get BTU/(lb·°F). For example, 10 kJ/(kg·K) = 2.388458966 BTU/(lb·°F).

How many BTU/(lb·°F) is 1 kJ/(kg·K)?

1 kJ/(kg·K) = 0.2388458966 BTU/(lb·°F), and 1 BTU/(lb·°F) = 4.1868 kJ/(kg·K).

Does this specific heat capacity converter work offline?

Yes. After the page has loaded once, all calculations run in your browser, so it keeps working without an internet connection.

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